The solids sodium chloride and sodium iodide both react with concentrated sulfuric acid at room temperature.
With $NaCl$ , the products are $NaHS{O_4}$ and $HCl{\text{ }}$.
With NaI, the products are $NaHS{O_4},{\text{ }}HI,{\text{ }}{I_2},{\text{ }}S{O_2},{\text{ }}{H_2}O,{\text{ }}S$ and ${H_2}S$.
What is the explanation for this difference in products?
1 )
Chloride ions will displace iodine from the solution.
2 )
Hydrogen chloride is more volatile than hydrogen iodide.
Iodide ions are better reducing agents than chloride ions.
4 )
Sulfuric acid is able to act as a dehydrating agent with NaI.
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