Calcium carbide, $Ca{C_2}$, reacts with water, as shown. The data below the equation show, in $kJmo{l^{-1}},$ the standard enthalpies of formation of the compounds involved.
$\eqalign{
& Ca{C_2}\left( s \right) + {H_2}O\left( l \right) \to CaO\left( s \right) + {C_2}{H_2}\left( g \right) \cr
& \,\,-60{\text{ }}\,\,\,\,\,\,\,\,\,\,-286{\text{ }}\,\,\,\,\,\,\,\,\,\,\,-635{\text{ }}\,\,\,\,\,\,\,{\text{ }} + 228 \cr} $
What is the standard enthalpy change of the reaction shown?
1 )
$-753{\text{ }}kJ{\text{ }}mo{l^{-1}}{\text{ }}$
$-61{\text{ }}kJ{\text{ }}mo{l^{-1}}{\text{ }}$
3 )
$ + 61{\text{ }}kJ{\text{ }}mo{l^{-1}}{\text{ }}$
4 )
$ + 753{\text{ }}kJ{\text{ }}mo{l^{-1}}{\text{ }}$
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