A wire is fixed at one end and is extended by a force ${F_1}$ acting on the other end. This causes the wire to have an elastic potential energy of $0.15 J$.
The force applied to the wire is now changed to a force ${F_2}$. This causes the wire to have a new elastic potential energy of $0.60 J$.
The wire obeys Hooke’s law.
What is the relationship between ${F_1}$and ${F_2}$?
1 )
$F_1 = 2F_2$
2 )
$F_1 = 4F_2$
$2F_1 = F_2$
4 )
$4F_1 = F_2$
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