$LiAl{\text{ }}{H_4}$ contains $AlH_4^ - $ ions in which aluminium has an oxidation state of +3.
$LiAl{\text{ }}{H_4}$ reacts with water, as shown.
$LiAl{\text{ }}{H_4} + 4{H_2}O \to 4{H_2} + LiOH + Al{\left( {OH} \right)_3}$
In this reaction, each of the four water molecules produces one hydroxide ion. It does this by losing
one ${H^ + }$ ion, which reacts with the $LiAl{\text{ }}{H_4}$.
Which changes in oxidation number occur in this reaction?
1 )
Al increases by 1 and H decreases by 1.
2 )
H decreases by 2 and also increases by 1.
H increases by 1 and also decreases by 1.
4 )
O decreases by 1 and H increases by 1.
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