A uniform bar of length $L$ and weight $W$ rests horizontally on two supports $X$ and $Y$.
Support $X$ exerts a vertical force $R_X$ at a distance of $\frac{L}{6}$ from one end of the bar.
Support $Y$ exerts a vertical force $R_Y$ at the other end of the bar.
The bar is in equilibrium.
What is the ratio $\frac{{{R_X}}}{{{R_Y}}}$?

$\frac{3}{2}$
2 )
$\frac{2}{3}$
3 )
$\frac{3}{5}$
4 )
$\frac{2}{5}$
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