In an investigation, a plant cell was placed in pure water.
The initial rate at which water molecules entered the cell, R, was greater than the initial rate at which water molecules left the cell.
In a second investigation, a plant cell of the same type was placed in a solution with a water potential equal to that of the cell contents.
What will happen in the second investigation over a period of five minutes?
1 )
Water molecules will not enter or leave the cell because the water potential of the cell contents is equal to that of the solution.
Water molecules will enter and leave the cell in equal amounts, both at an initial rate that is less than R in the first investigation.
3 )
Water molecules will enter and leave the cell in equal amounts, both at an initial rate that is greater than R in the first investigation.
4 )
Water molecules will enter and leave the cell in equal amounts, both at an initial rate that is equal to R in the first investigation.
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