A bag contains 3 red balls and 4 blue balls. What is the probability of drawing a red ball AND a blue ball in two draws without replacement?
$\frac{3}{7} \times \frac{4}{6}$
2 )
$\frac{3}{7} + \frac{4}{6}$
3 )
$\frac{3}{7} \times \frac{4}{7}$
4 )
$\frac{3}{7} + \frac{4}{7}$
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