The equation for the reaction between aqueous copper ions and aqueous iodide ions is as follows.
2Cu$^{2+}$(aq) + 4I$^–$(aq) → 2CuI(s) + I$_2$(aq)
What is the change in oxidation state of copper?
1 )
+2 to –1
2 )
+2 to 0
+2 to +1
4 )
+4 to +2
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