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$ABC$ is a vertical cross-section of a surface. The part of the surface containing $AB$ is smooth and $A$ is $4{\text{ }}m$ higher than $B$. The part of the surface containing $BC$ is horizontal and the distance $BC$ is $5{\text{ }}m$ (see diagram). A particle of mass $0.8{\text{ }}kg$ is released from rest at $A$ and slides along $ABC$. Find the speed of the particle at $C$ in each of the following cases.

a) The horizontal part of the surface is smooth.

b) The coefficient of friction between the particle and the horizontal part of the surface is 0.3.

پاسخ تشریحی :
نمایش پاسخ

a) $0.8g \times 4$

$\left[ {{\raise0.5ex\hbox{$\scriptstyle 1$}
\kern-0.1em/\kern-0.15em
\lower0.25ex\hbox{$\scriptstyle 2$}}0.8{v^2} = 32} \right]$

Speed at $C = 8.94{\text{ }}m{s^{ - 1}}$

b) $[Either{\text{ }}F = 0.3\left( {0.8g} \right)$ and $ - 2.4 = 0.8a$ or

$F = 0.3\left( {0.8g} \right)$ and $WD = 2.4 \times 5]$

$[{v^2} = ans{\left( a \right)^2} - 2 \times 3 \times 5$ or ${\raise0.5ex\hbox{$\scriptstyle 1$}
\kern-0.1em/\kern-0.15em
\lower0.25ex\hbox{$\scriptstyle 2$}}0.8{v^2} = 32 - 12]$

Speed at $C = 7.07{\text{ }}m{s^{ - 1}}$

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