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In a group of 30 teenagers, 13 of the 18 males watch ‘Kops are Kids’ on television and 3 of the 12 females watch ‘Kops are Kids’.

a) Find the probability that a person chosen at random from the group is either female or watches ‘Kops are Kids’ or both.

b) Showing your working, determine whether the events ‘the person chosen is male’ and ‘the person chosen watches Kops are Kids’ are independent or not.

پاسخ تشریحی :
نمایش پاسخ

a) $P\left( F \right) = \frac{{12}}{{30}}\left( {0.4} \right)$

or $P\left( W \right) = \frac{{16}}{{30}}\left( {0.533} \right)$

or $P\left( {M \cap W'} \right) = \frac{5}{{30}}\left( {0.167} \right)$

($F$ or $W$) $ = \frac{{13}}{{30}} + \frac{3}{{30}} + \frac{9}{{30}}$

or $1 - \frac{5}{{30}}$ or $\frac{{12}}{{30}} + \frac{{16}}{{30}} - \frac{3}{{30}}$

$ = \frac{5}{6}\left( {0.833} \right)$

b) $P\left( M \right) = 18/30{\text{ }}\left( {0.6} \right)$,

$P\left( W \right) = 16/30{\text{ }}\left( {0.533} \right)$,

$P\left( M \right) \times P\left( W \right) = 8/25{\text{ }}\left( {0.32} \right)$

$P$($M$ and $W$) $ = 13/30{\text{ }}\left( {0.433} \right)$

$ \ne 8/25{\text{ }}\left( {0.32} \right)$

not independent

OR

$P\left( {M|W} \right) = \frac{{P\left( {M\,and\,W} \right)}}{{P\left( W \right)}} = \frac{{{\raise0.5ex\hbox{$\scriptstyle {13}$}
\kern-0.1em/\kern-0.15em
\lower0.25ex\hbox{$\scriptstyle {30}$}}}}{{{\raise0.5ex\hbox{$\scriptstyle {16}$}
\kern-0.1em/\kern-0.15em
\lower0.25ex\hbox{$\scriptstyle {30}$}}}} = \frac{{13}}{{16}}\,\,\left( {0.813} \right)$

$ \ne \frac{{18}}{{30}} = P\left( M \right)$,

not independent

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