A force $F$ is applied at an angle of $45°$ to a door handle at a distance d from the pivot of the handle, as shown.
What is the moment of the force about the pivot?

\(\frac{Fd}{\sqrt{2}}\)
2 )
\( Fd \)
3 )
\( Fd\sqrt{2} \)
4 )
\( 2Fd \)
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