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A ball moves on the horizontal surface of a billiards table with deceleration of constant magnitude $d{\text{ }}m{\text{ }}{s^{ - 2}}$. The ball starts at $A$ with speed $1.4{\text{ }}m{\text{ }}{s^{ - 1}}$ and reaches the edge of the table at $B$, $1.2{\text{ }}s$ later, with speed $1.1{\text{ }}m{\text{ }}{s^{ - 1}}$.

a) Find the distance $AB$ and the value of $d$.

$AB$ is at right angles to the edge of the table containing $B$. The table has a low wall along each of its edges and the ball rebounds from the wall at $B$ and moves directly towards $A$. The ball comes to rest at $C$ where the distance $BC$ is $2{\text{ }}m$.

b) Find the speed with which the ball starts to move towards $A$ and the time taken for the ball to travel from $B$ to $C$.

c) Sketch a velocity-time graph for the motion of the ball, from the time the ball leaves $A$ until it comes to rest at $C$, showing on the axes the values of the velocity and the time when the ball is at $A$, at $B$ and at $C$. 

پاسخ تشریحی :
نمایش پاسخ

a) $\left[ {s = {\raise0.5ex\hbox{$\scriptstyle 1$}
\kern-0.1em/\kern-0.15em
\lower0.25ex\hbox{$\scriptstyle 2$}}\left( {1.4 + 1.1} \right) \times 1.2;{\text{ }}1.1 = 1.4 + \left( { - d} \right) \times 1.2} \right]$

$AB = 1.5{\text{ }}m$ or $d = 0.25$

$d = 0.25$ or $AB = 1.5{\text{ }}m$

b) $[0 = {u^2} + 2\left( { - 0.25} \right)2;$

$2 = 0 - {\raise0.5ex\hbox{$\scriptstyle 1$}
\kern-0.1em/\kern-0.15em
\lower0.25ex\hbox{$\scriptstyle 2$}}\left( { - 0.25} \right){t^2}]$

Speed is $1{\text{ }}m{s^{ - 1}}$ or time is $4{\text{ }}s$

Time is 4 s or speed is $1{\text{ }}m{s^{ - 1}}$

c) For line joining $\left( {0,{\text{ }}1.4} \right)$ and $\left( {1.2,{\text{ }}1.1} \right)$

For line joining $\left( {1.2,{\text{ }} - 1} \right)$ and $\left( {5.2,{\text{ }}0} \right)$

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