Iodine and propanone react according to the following equation.
${I_2}\left( {aq} \right) + C{H_3}COC{H_3}\left( {aq} \right) \to C{H_3}COC{H_2}I\left( {aq} \right) + HI\left( {aq} \right)$
If the concentration of propanone is increased, keeping the total reaction volume constant, the initial rate of the reaction also increases.
What could be the reason for this?
1 )
A greater proportion of collisions are successful at the higher concentration.
2 )
The particles are further apart at the higher concentration.
3 )
The particles have more energy at the higher concentration.
There are more collisions per second between particles at the higher concentration.
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