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جستجو

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Solve the equation

$ln\left( {1 + {x^2}} \right) = 1 + 2{\text{ }}ln{\text{ }}x$,

giving your answer correct to 3 significant figures.

پاسخ تشریحی :
نمایش پاسخ

Use law for the logarithm of a power, a quotient, or a product correctly at least once

Use ln $e = 1$ or $e = exp\left( 1 \right)$

Obtain a correct equation free of logarithms, e.g. $1 + {x^2} = e{x^2}$

Solve and obtain answer $x = 0.763$ only

[For the solution $x = 0.763$ with no relevant working give B1, and a further B1 if 0.763 is shown to be the only root.]

[Treat the use of logarithms to base 10 with answer 0.333 only, as a misread.]

[SR: Allow iteration, giving B1 for an appropriate formula,

e.g. ${x_{n + 1}} = \exp \left( {\left( {ln\left( {1 + {x_n}^2} \right) - 1} \right)/2} \right)$, M1 for using it correctly once, A1 for 0.763, and A1 for showing the equation has no other root but 0.763.]

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